FSA Concatenation

With $M,M^{\prime }$ as DFSA We want $M_{\cdot }$, s.t $\mathcal{L}(M_{\cdot })=\mathcal{L}(M)\mathcal{L}(M^{\prime })$

Intuition

All the exit states in $M$, will then have a transition to the initial state of $M^{\prime }$