A method for evaluating limits in two dimensions. For Substitute , Then, you get
A method for evaluating limits in two dimensions. For lim(x,y)→(0,0)f(x,y) Substitute x=rcosθ, y=rsinθ Then, you get limr→0f(rcosθ,rsinθ)
lim(x,y)→(0,0)x2+y23x2y=limr→0r2cos2θ+r2sin2θ3r2cos2θrsinθ=limr→0r23r3cosθsinθ=0